TASK 2: "GROUP OF WORKERS" - SOLUTION

Explanation:

If n workers complete the work in a certain time s, then with more workers (n+m) the work will be completed proportionally less as many times as the number of workers has increased, i.e. (n+m) / n times. For example, if n= 10 and m=5, the number of workers is increased from 10 to 15, i.e. 15/10=1.5 times. The same work will then be completed in 1.5 times less time (inverse proportionality). So, the proportion:

A group of workers - a solution in the C programming language

​#include <stdio.h>

using namespace std;

int main()
{
 int n,m;                                                         // n-number of workers at the beginning, m-number of added workers
doubles,t;                                                 //s- Time it takes n workers to finish the job
//t- Time it takes n + m workers to complete the same job
scanf("%d%lf%d", &n, &s, &m);     //Reading
                                                                          / * t: s = n: (n + m) * / / * proportion * /
                                                                          / * t = n * s / (n + m) * // * solution of proportion * /
    t=n*s/(n+m);                                              // time to n + m workers, obtained by proportion
printf("%.2f",t);                                         // Print results
    return 0;
}

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A group of workers - a solution in the programming language JAVA

public static void main(String[] args) {

        Scanner ucitavac = new Scanner(System.in);
int n, m;            // n-number of workers at the beginning, m-number of added workers
double s, t;          //s- time required for n workers to complete the job
//t- time required for n+m workers to complete the same job

  //učitavanje
        System.out.println("Enter the initial number of workers n=?");
        n = ucitavac.nextInt();
        System.out.println("Enter the additional number of workers m=?");
        m = ucitavac.nextInt();
        System.out.println("Enter the time it takes n workers to complete the job");
        s = ucitavac.nextInt(); //end of loading

/*t:s=n:(n+m)*/ /*proportion*/
/* t=n*s/(n+m)*//* proportion solution*/
        t = n * s / (n + m);        // time to n+m workers, obtained by proportion
        System.out.printf("%.2f", t);  //Print the results​
    }